Hello! 欢迎来到小浪资源网!



解释像耳朵一样的甜甜圈(最后部分)


解释像耳朵一样的甜甜圈(最后部分)

c 的完整代码是

#include <math.h> #include <stdio.h> #include <string.h> #include <unistd.h>  typedef struct {     double a1;     double a2;     double a3; } singlerow;  typedef struct {     singlerow a1;     singlerow a2;     singlerow a3; } matrix;  singlerow multiply(singlerow m1, matrix m2) {     singlerow res;     res.a1 = m1.a1 * m2.a1.a1 + m1.a2 * m2.a2.a1 + m1.a3 * m2.a3.a1;     res.a2 = m1.a1 * m2.a1.a2 + m1.a2 * m2.a2.a2 + m1.a3 * m2.a3.a2;     res.a3 = m1.a1 * m2.a1.a3 + m1.a2 * m2.a2.a3 + m1.a3 * m2.a3.a3;     return res; }  int main() {   int screen_width = 80, height = 22;   char buffer[1760];   float zbuffer[1760];   float a = 0, b = 0;   int r2 = 2, r1 = 1;   printf("");   while (1) {     memset(buffer, ' ', 1760);     memset(zbuffer, 0, 7040);       for (float theta = 0; theta < 6.28; theta += 0.07) {         for (float phi = 0; phi < 6.28; phi += 0.02) {           singlerow circle = {2 + cos(theta), sin(theta), 0};           // rotation on y-axis           matrix ry = {{cos(phi), 0, sin(phi)}, {0, 1, 0}, {-sin(phi), 0, cos(phi)}};           // rotation on x-axis           matrix rx = {{1, 0, 0}, {0, cos(a), sin(a)}, {0, -sin(a), cos(a)}};           // rotation on z-axis           matrix rz = {{cos(b), sin(b), 0}, {-sin(b), cos(b), 0}, {0, 0, 1}};            singlerow donut = multiply(circle, ry);           singlerow rotatex = multiply(donut, rx);           // we will consider it as [nx, ny, nz]           singlerow spinningdonut = multiply(rotatex, rz);           float recinz = 1 / (spinningdonut.a3 + 5);            int x = 40 + 30 * spinningdonut.a1 * recinz;           int y = 12 + 15 * spinningdonut.a2 * recinz;            // o is index of current buffer           int o = x + screen_width * y;            int l = 8 * (spinningdonut.a2 - spinningdonut.a3 + 2 * cos(b) * sin(a) * sin(phi)             - 2 * cos(phi) * cos(theta) * sin(b)             - 2 * cos(phi) * sin(b)             + 2 * cos(a) * sin(phi)           );            // donut luminicity will be seen by these characters           // these 12           char charout[] = ".,-~:;=!*#$@";            if (x < screen_width && y < height && zbuffer[o] < recinz) {             zbuffer[o] = recinz;             // if l < 0, . will be buffer             buffer[o] = charout[l > 0 ? l : 0];           }         }       }     // clear screen     printf("");     for (int i = 0; i <1761; i++) {       // on every 80th character, new line will be printed       // if there's a reminder then buffer printed       putchar(i % 80 ? buffer[i] : 10);       a += 0.00004;       b += 0.00002;     }     // timer to slow down speed a bit     usleep(10000);   }   return 0; } 

Java的完整代码是

import java.util.Arrays;  class singleRow {   public double a1;   public double a2;   public double a3;   public singleRow(double a1, double a2, double a3) {     this.a1 = a1;     this.a2 = a2;     this.a3 = a3;   } } class Matrix {   public singleRow a1;   public singleRow a2;   public singleRow a3;   public Matrix(singleRow a1, singleRow a2, singleRow a3) {     this.a1 = new singleRow(a1.a1, a1.a2, a1.a3);     this.a2 = new singleRow(a2.a1, a2.a2, a2.a3);     this.a3 = new singleRow(a3.a1, a3.a2, a3.a3);   }   public static singleRow multiply(singleRow m1, Matrix m2) {     singleRow res = new singleRow(0, 0, 0);     res.a1 = (m1.a1 * m2.a1.a1) + (m1.a2 * m2.a2.a1) + (m1.a3 * m2.a3.a1);     res.a2 = (m1.a1 * m2.a1.a2) + (m1.a2 * m2.a2.a2) + (m1.a3 * m2.a3.a2);     res.a3 = (m1.a1 * m2.a1.a3) + (m1.a2 * m2.a2.a3) + (m1.a3 * m2.a3.a3);     return res;   } }   public class Main { public static void main() {   int screen_width = 80, height = 22;   char[] buffer = new char[1760];   double[] zBuffer = new double[1760];   double A = 0, B = 0;   int R2 = 2, R1 = 1;   System.out.print("u001b[2J");   while (true) {     Arrays.fill(buffer, 0, 1760, ' ');     Arrays.fill(zBuffer, 0, 1760, 0);       for (float theta = 0; theta < 6.28; theta += 0.07) {         for (float phi = 0; phi < 6.28; phi += 0.02) {           singleRow circle = {2 + Math.cos(theta), Math.sin(theta), 0};           // rotation on Y-axis           Matrix Ry = new Matrix(           new singleRow(Math.cos(phi), 0, Math.sin(phi)),           new singleRow(0, 1, 0),           new singleRow(-Math.sin(phi), 0, Math.cos(phi))         );         // rotation on X-axis         Matrix Rx = new Matrix(           new singleRow(1, 0, 0),           new singleRow(0, Math.cos(A), Math.sin(A)),           new singleRow(0, -Math.sin(A), Math.cos(A))         );         // rotation on Z-axis         Matrix Rz = new Matrix(           new singleRow(Math.cos(B), Math.sin(B), 0),           new singleRow(-Math.sin(B), Math.cos(B), 0),           new singleRow(0, 0, 1)         );            singleRow donut = Matrix.multiply(circle, Ry);           singleRow rotateX = Matrix.multiply(donut, Rx);           // We will consider it as [Nx, Ny, Nz]           singleRow spinningDonut = Matrix.multiply(rotateX, Rz);           float reciNz = 1 / (spinningDonut.a3 + 5);            int x = 40 + 30 * spinningDonut.a1 * reciNz;           int y = 12 + 15 * spinningDonut.a2 * reciNz;            // o is index of current buffer           int o = x + screen_width * y;            int L = 8 * (spinningDonut.a2 - spinningDonut.a3              + 2 * Math.cos(B) * Math.sin(A) * Math.sin(phi)             - 2 * Math.cos(phi) * Math.cos(theta) * Math.sin(B)             - 2 * Math.cos(phi) * Math.sin(B)             + 2 * Math.cos(A) * Math.sin(phi)           );            // donut luminicity will be seen by these characters           // these 12           char[] charOpts = {'.', ',', '-', '~', ':', ';', '=', '!', '*', '#', '$', '@'};            if (x < screen_width && y < height && zBuffer[o] < reciNz) {             zBuffer[o] = reciNz;             // If L < 0, . will be buffer             buffer[o] = charOut[L > 0 ? L : 0];           }         }       }     // Clear screen     System.out.print("u001b[H");     for (int i = 0; i <1761; i++) {       // On every 80th character, new line will be printed       // If there's a reminder then buffer printed       System.out.print(i % 80 ? buffer[i] : 10);       A += 0.00004;       B += 0.00002;     }   } } } 

相关阅读