如何利用 Sequelize 实现复杂的组合查询条件？

// 这里以查询 `name` 为 `张三`、`age` 为 `18` 的数据为例 let where = {   name: '张三', // 直接赋值   age: { [op.eq]: 18 } // 使用 op.eq 进行等于比较 };  let params = {}; if (object.keys(where).length !== 0) {   params['where'] = where; }  let item = awAIt test.findone(params);

// 前端组装成这样的数据： let list = [   {     "field" : "name",     "value" : "张三",     "op" : 'and',     "action" : 'like'   },   {     "field" : "age",     "value" : 18,     "op" : 'and',     "action" : 'eq'   },   {     "field" : "city",     "value" : "北京",     "op" : 'or', // OR 条件     "action" : 'like'   } ];  // 拆分数组 let andWhere = []; let orWhere = []; for (const item of list) {   if (item.op === 'and') {     andWhere.push(item);   } else if (item.op === 'or') {     orWhere.push(item);   } }  // 拼接 where 条件 let where = {}; for (const item of andWhere) {   if (item.action === 'like') {     where[item.field] = { [Op.like]: `%${item.value}%` }   } else {     where[item.field] = item.value;   } }  if (orWhere.length > 0) {   let or = [];   for (const item of orWhere) {     if (item.action === 'like') {       or.push({ [item.field]: { [Op.like]: `%${item.value}%` } });     } else {       or.push({ [item.field]: item.value });     }   }    where[Op.or] = or; }  let params = {}; if (Object.keys(where).length !== 0) {   params['where'] = where; }  let item = await Test.findOne(params);